We’re using the L6920 to drive a 1-watt LED.
We’re trying to apply the under voltage cut-off ( lockout) too. We chose the values of the voltage ground connected to the LBI pin similar that the value that comes to say 3V. Still, the IC didn’t shut off at 3V.
We also tried connecting the LBO to Vout with a 200K resistor in between. Even this didn’t work.
Can someone help apply this circuit?
Thanks!
Hi Ashish, However, you would notice that LBI input is connected to LBO output and that's the only purpose of this input, If you look into the block diagram of L6920 in its datasheet. LBI input doesn't shut down the output! Still, you need to use LBO output to shut down accordingly, If you require tRead more
Hi Ashish,
However, you would notice that LBI input is connected to LBO output and that’s the only purpose of this input, If you look into the block diagram of L6920 in its datasheet. LBI input doesn’t shut down the output!
See lessStill, you need to use LBO output to shut down accordingly, If you require to shut down the output.