We’re using the L6920 to drive a 1-watt LED.
We’re trying to apply the under voltage cut-off ( lockout) too. We chose the values of the voltage ground connected to the LBI pin similar that the value that comes to say 3V. Still, the IC didn’t shut off at 3V.
We also tried connecting the LBO to Vout with a 200K resistor in between. Even this didn’t work.
Can someone help apply this circuit?
Thanks!